求助:控制芯片在次級,電源怎么啟動?
這個是電路圖,我看不明白啟動電路。
原文就這么一點文字描述。Start-up circuit
As already mentioned in the introduction section, the controller is located on the secondary side of the power
transformer, and for this reason, a start-up circuit has to be provided for a correct system activation.
The start-up circuit is based on a diac sending a train of controlled pulses to the low side drive section; the floating
drive section is energised by the second secondary gate driv e transformer winding .
As soon as the L5991a wakes-up, it generates a pwm signal enabling the start-up circuit.
啟動電路
由于已經(jīng)在引言部分提到,位于電源的二次側(cè)控制器變壓器,因為這個原因,啟動電路必須提供正確的系統(tǒng)激活。
發(fā)送DIAC 低側(cè)驅(qū)動部分 列車的控制脈沖啟動電路是基于浮動
驅(qū)動部分由第二柵極驅(qū)動變壓器繞組通電。一旦作為L5991a喚醒的,它會產(chǎn)生一個PWM信號,使啟動電路。
這樣分析對不對:開機后,當C25電壓充到32V時,DB3導通,電壓加到驅(qū)動繞組上,相互耦合,上管也感應(yīng)出電壓,此時上下管導通。此時傳遞能量到次級。延遲零點幾uS(R20C28的時間常數(shù)為2.5uS0后,C28充電試三極管T3導通,驅(qū)動線圈無電壓,上下管截止。如果一次啟動的能量不夠,延遲幾個mS(R16C25的時間常數(shù)36mS),DB3再次導通。
電路正常后,DB3是會周期導通。如果導通時間剛好是開關(guān)管截止時間,會短時間把開關(guān)管再次導通,對電路還是有點影響。